SOLUTION: Hi, I'm going back to college and I've forgotten.. well, everything about math. Please explain to me how to do this. An eastbound car is going 4 miles per hour faster than a westb

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Question 946201: Hi, I'm going back to college and I've forgotten.. well, everything about math. Please explain to me how to do this.
An eastbound car is going 4 miles per hour faster than a westbound car. The cars are 208 miles apart
2 hours after passing each other on a highway. What is the speed, in miles per hour, of the eastbound car?
Found 2 solutions by Fombitz, lwsshak3:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Rate x Time = Distance
.
.
.
When they pass each other, the distance between them is zero.
The first car is going X mph west and it's distance from the meet point is, X%2At.
The second car is going X%2B4 mph east and its distance from the meet point is %28X%2B4%29t
.
.

So after two hours, the distance would be,
2X%2B2%28X%2B4%29=208
Now you have 1 equation in 1 unknown variable, you can solve.
2X%2B2X%2B8=208
4X=200
X=50mph
The eastbound car is going 50%2B4=54 mph.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
An eastbound car is going 4 miles per hour faster than a westbound car. The cars are 208 miles apart2 hours after passing each other on a highway. What is the speed, in miles per hour, of the eastbound car?
***
let x=speed of eastbound car
x-4=speed of westbound car
travel time*speed=distance
***
2x+2(x-4)=208
2x+2x-8=208
4x=216
x=54
speed of eastbound car=54 mph