SOLUTION: What is the number of sides of a polygon if the sum of the measures of its interior angles is twice the sum of the measures of its exterior angles

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Question 946012: What is the number of sides of a polygon if the sum of the measures of its interior angles is twice the sum of the measures of its exterior angles
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of the measures of the exterior angles is 360%5Eo >
(It is so because each exterior angle is the angle that your direction changes at a vertex as you go around the polygon,
and one turn around the polygon is a 360%5Eo turn).
If the sum of the measures of a polygon's interior angles is twice the sum of the measures of its exterior angles, then it is
2%2A360%5Eo=red%28720%5Eo%29
The sum of the measures of the interior angles of a polygon depends on the number of sides of the polygon, n ,
and is green%28%28n-2%29%2A180%5Eo%29 .
For this problem,
green%28%28n-2%29%2A180%5Eo%29=red%28720%5Eo%29--->n-2=720%5Eo%2F180%5Eo--->n-2=4--->n=4%2B2--->highlight%28n=6%29