Question 945992: twenty kilograms of nuts consisting of cashews worth $6.00 per kg, pecans worth $2.50 per kg, and peanuts worth $1.50 per kg are mixed. there are twice as many pecans as cashews, and there are as many kilograms of peanuts as pecans. the total value of nuts is $56. how many of each are there? must be solved algebraically using the 5 steps.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! twenty kilograms of nuts consisting of cashews worth $6.00 per kg, pecans worth $2.50 per kg, and peanuts worth $1.50 per kg are mixed. there are twice as many pecans as cashews, and there are as many kilograms of peanuts as pecans. the total value of nuts is $56. how many of each are there? must be solved algebraically using the 5 steps.
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Equations:
h + c + p = 20 kg
6h+2.5c+1.5p = 56 dollars
p = c
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Modify::
Substitute c for "p" to get:
h + 2c = 20
6h + 4c = 56
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Modify::
h + 2c = 20
3h + 2c = 28
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Subtract::
2h = 8
h = 4 kg (amt. of cashews needed)
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4+ 2c = 20
2c = 16
c = 8 kg (amt. of picans needed)
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Solve for "p"::
h + c + p = 20 kg
4 + 8 + p = 20
p = 8 kg (amt. of peanuts needed)
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Cheers,
Stan H.
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