SOLUTION: Divide.simplify so that there are no radicals in the denominator.√3/25... √27-√30/√3... 9/√4... Plz help i need to finish this today.

Algebra ->  Finance -> SOLUTION: Divide.simplify so that there are no radicals in the denominator.√3/25... √27-√30/√3... 9/√4... Plz help i need to finish this today.      Log On


   

Question 945861: Divide.simplify so that there are no radicals in the denominator.√3/25...
√27-√30/√3...
9/√4...
Plz help i need to finish this today.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
if you have this:
1.
sqrt%283%29%2F25
2.
%28sqrt%2827%29-sqrt%2830%29%29%2Fsqrt%283%29
3.
9%2Fsqrt%284%29
then, you can simplify like following:
sqrt%283%29%2F25...already simplest form; or, as decimal number sqrt%283%29%2F25=0.069282 approximately

2.
%28sqrt%2827%29-sqrt%2830%29%29%2Fsqrt%283%29...multiply bot numerator and denominator by sqrt%283%29
%28sqrt%283%29%28sqrt%2827%29-sqrt%2830%29%29%29%2F%28sqrt%283%29sqrt%283%29%29


%28sqrt%283%29%28sqrt%283%5E3%29-sqrt%283%2A2%2A5%29%29%29%2F%28sqrt%283%29%29%5E2

%28sqrt%283%5E4%29-%28sqrt%283%29sqrt%283%29sqrt%282%29sqrt%285%29%29%29%2F3

%28sqrt%28%283%5E2%29%5E2%29-%28sqrt%283%5E2%29sqrt%282%29sqrt%285%29%29%29%2F3

%28sqrt%289%5E2%29-%283sqrt%282%29sqrt%285%29%29%29%2F3

%289-3sqrt%282%29sqrt%285%29%29%2F3

%28cross%289%293-cross%283%29sqrt%282%29sqrt%285%29%29%2Fcross%283%29

3-sqrt%282%29sqrt%285%29

3.
9%2Fsqrt%284%29
9%2Fsqrt%282%5E2%29
9%2F2