Question 945776: The percentage of salt in 1L of water is 10%. If 500 mL of water is added to this mixture, what percentage of salt is there now? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! The percentage of salt in 1L of water is 10%. If 500 mL of water is added to this mixture, what percentage of salt is there now?
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1L=1000 mL
amt of salt in 1L=10%*1000=100 mL
percentage of salt in mixture=100/(1000+500)=100/1500=6 2/3%