SOLUTION: Log2^x+log4^x+log8^x=21/4, find x

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Question 945773: Log2^x+log4^x+log8^x=21/4, find x
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Log2^x+log4^x+log8^x=21/4, find x
log%28%282%5Ex%2A4%5Ex%2A8%5Ex%29%29=21%2F4
log%28%282%5E%28x%29%2A2%5E%282x%29%2A2%5E%283x%29%29%29=21%2F4
log%28%282%5E%286x%29%29%29=21%2F4
6xlog%282%29=21%2F4
6x=21/4log2
x=21/(24log2)
x≈2.9067