SOLUTION: Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 378 miles in the same length of time Dana travels 354 miles. If Chuck's rate of travel is 4 mph more than Dan

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Question 945721: Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 378 miles in the same length of time Dana travels 354 miles. If Chuck's rate of travel is 4 mph more than Dana's, and they travel the same length of time, at what speed does Chuck travel?
How do I even begin to set this up? How do I solve it?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Chuck and Dana agree to meet in Chicago for the weekend.
Chuck travels 378 miles in the same length of time Dana travels 354 miles.
If Chuck's rate of travel is 4 mph more than Dana's, and they travel the same length of time, at what speed does Chuck travel?
:
let s = Chuck's rate of travel
then
(s-4) = Dana's travel
:
Their times are equal, write a time equation; time = dist/speed
378%2Fs = 354%2F%28%28s-4%29%29
Cross multiply, solve for s