Question 945715: Find the area of a rhombus whose longer diagonal is 24 ft and the length of each side is 8|3 ft (the random line "|" is supposed to represent square root). So, this is what I already have, I'm not sure if it's right or not but this is it:
When the diagonal are drawn, we get 4 congruent isosceles right triangles. The hypotenuse of all the triangles is 8|3 (again the line "|" represents the square root") and one of the legs is 12 (because 24/2 =12). Next, I used the Pythagorean Theorem and plugged in what I know: 12^2 + x^2 = 8|3^2 (the line is the square root) and then I got: 144 + x^2 = 192. (I'm not sure if the "192" is right or not) then, x^2 = 48, then, x= |16|3 (the line is the square root) then, x= 4|2, (the line is the square root). Now since that is the leg of the triangle, also half of the diagonal, will the whole diagonal be 8|3? (Again the line is the square root).then, I would do 24·(8|3)·.5 to find the area of the rhombus. (Again the line is the square root). Thank you for helping me and taking your time out of your lives to be so kind to help me, it really is nice and .what could help me in the future is, when u have a number next to a square root, and there is also an exponent, do u distribute the exponent to the square root and the number? I was kinda confused. Anyways, thank you again, I appreciate it!
Answer by MathLover1(20850)   (Show Source):
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