SOLUTION: milk and water are mixed in a vessel A in a ratio of 5:2 and in a vessels B in the ratio of 8:5 . In what ratio should quantities be taken from the two vessels so as to form a

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: milk and water are mixed in a vessel A in a ratio of 5:2 and in a vessels B in the ratio of 8:5 . In what ratio should quantities be taken from the two vessels so as to form a       Log On


   

Question 945624: milk and water are mixed in a vessel A in a ratio of 5:2 and in a vessels B in the ratio of 8:5 . In what ratio should quantities be taken from the two vessels so as to form a mixture , in which milk and water will be in the ratio of 9:4 ?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Change to concentrations as fraction as milk.

Vessel A: 5%2F7
Vessel B: 8%2F13
Expected Mixture Revision: 9%2F13

Taking just a guess, trying to finish having a total number of 7%2A13=91 parts.

Taking x parts from vessel A and y parts from vessel be for a total of 91 parts and expected this concentration of 9%2F13.....

%28%285%2F7%29x%2B%288%2F13%29y%29%2F91=%289%2F13%29 and x%2By=91

When the set of equations makes sense, then you can finish solving for x and y and their ratio with no real trouble, but just several algebra steps. You may want to begin by multiplying the rational or complex fractional equation's left side by 1 in the form of 91%2F91.