SOLUTION: Solve the equation cotangent squared of the quantity of pi over 2 minus theta = secant of theta + 1 for for theta greater than or equal to 0 but less than 2 pi.

Algebra ->  Trigonometry-basics -> SOLUTION: Solve the equation cotangent squared of the quantity of pi over 2 minus theta = secant of theta + 1 for for theta greater than or equal to 0 but less than 2 pi.       Log On


   

Question 945487: Solve the equation cotangent squared of the quantity of pi over 2 minus theta = secant of theta + 1 for for theta greater than or equal to 0 but less than 2 pi.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the equation cotangent squared of the quantity of pi over 2 minus theta = secant of theta + 1 for for theta greater than or equal to 0 but less than 2 pi.
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use x for theta
cot%5E2%28pi%2F2-x%29=secx%2B1
tan%5E2%28x%29=1%2Fcosx%2B1
sin%5E2%28x%29%2Fcos%5E2%28x%29=1%2Fcosx%2B1
lcd: cos^2(x)
sin%5E2%28x%29=cosx%2Bcos%5E2%28x%29
1-cos%5E2%28x%29=cosx%2Bcos%5E2%28x%29
2cos^2(x)+cosx-1=0
(2cosx-1)(cosx+1)=0
cosx=1/2
x=π/3,5π/3
or
cosx=-1
x=π