SOLUTION: Please find all real values of k for which 3t^2-6t+k=0

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Question 94545: Please find all real values of k for which 3t^2-6t+k=0
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Quadratic formula%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a
Let k=c in the formula
Ifb%5E2-4akis negative then the answer will not be a real number because the square root of a negative number is not a real number.
a=3 b=-6 c=k
b%5E2=-6%5E2=36+ so must be -4ak%3E=-36.
-4%2A3%2Ak%3E=-36
-12k%3E=-36
divide both sides by -12. k%3C=3
So k must be greater than -infinityand less than or equal to 3
-infinity%3Ck%3E=3
EdJones