SOLUTION: the ratio in the ages of A,B,C, six years before was 2:3:5 if the sum of their present ages is 168, find their ages

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Question 945439: the ratio in the ages of A,B,C, six years before was 2:3:5 if the sum of their present ages is 168, find their ages
Answer by Fombitz(32388) About Me  (Show Source):
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1.A%2BB%2BC=168
.
.
%28A-6%29%2F%28B-6%29=2%2F3
3%28A-6%29=2%28B-6%29
3A-18=2B-12
2.3A-2B=6
.
.
%28B-6%29%2F%28C-6%29=3%2F5
5%28B-6%29=3%28C-6%29
5B-30=3C-18
3.5B-3C=12
From the eq. 1,
C=168-A-B
Substitute into eq. 3,
5B-3%28168-A-B%29=12
5B-504%2B3A%2B3B=12
4.3A%2B8B=516
Now subtract eq. 2 from eq. 4,
3A%2B8B-3A%2B2B=516-6
10B=510
B=51
Then,
3A%2B8%2851%29=516
3A%2B408=516
3A=108
A=36
and
A%2BB%2BC=168
36%2B51%2BC=168
87%2BC=168
C=81