SOLUTION: a person who is 6 feet tall walks away from a 50 foot tower toward the tip of the towers shadow. at a distance of 32 feet from the tower the persons shadow begins to emerge beyond
Algebra ->
Customizable Word Problem Solvers
-> Finance
-> SOLUTION: a person who is 6 feet tall walks away from a 50 foot tower toward the tip of the towers shadow. at a distance of 32 feet from the tower the persons shadow begins to emerge beyond
Log On
Question 945412: a person who is 6 feet tall walks away from a 50 foot tower toward the tip of the towers shadow. at a distance of 32 feet from the tower the persons shadow begins to emerge beyond the towers shadow.. How much farther must the person walk to be completely out of the towers window.? Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! Let's use ratios. At 32 feet out, the shadow of the persons head and the shadow of the tip of the tower are on top of each other.
The person is 6 feet tall, the tower is 50 feet tall and the person's is standing 32 feet from the tower.
We need to find the distance from where the person is standing to the tip of shadow. Let's call that distance x.
Using ratios, we know that ratio of the tower to the person's heights is the same as the ratio of their shadows. We know the person's shadow is x. We also know the tower's shadow is (32 + x). So
If the person walks another 4.37 feet, then she or he will be past the tip of the tower's shadow.
(