SOLUTION: find the measures of the angles of a triangle if the measure of one side is twice the measure of a second and the third angle measures two times the second decreased by 20
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Question 945236: find the measures of the angles of a triangle if the measure of one side is twice the measure of a second and the third angle measures two times the second decreased by 20 Found 3 solutions by lwsshak3, ikleyn, greenestamps:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! find the measures of the angles of a triangle if the measure of one side is twice the measure of a second and the third angle measures two times the second decreased by 20
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let x=2nd angle
2x=1st angle
2x-20=3rd angle
..
x+2x+2x-20=180
5x=200
x=40
2x=80
2x-20=60
..
measure of 2nd angle=40˚
measure of 1st angle=80˚
measure of 3rd angle=60˚
You can put this solution on YOUR website! .
find the measures of the angles of a triangle if the measure of one side is twice
the measure of a second and the third angle measures two times the second decreased by 20
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The problem's formulation is incorrect.
If to read it word-in-word as it is written, it is a compote of words, but not a Math problem.
My advise to the managers of this project is to remove this Math composer
from writing Math problems IMMEDIATELY.
It should be done 7 years ago - next day as you hired him.
find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second and the third angle measures two times the second decreased by 20
One angle (the "first" angle) has a measure equal to twice the measure of the second angle; the third angle has a measure that is 20 less than twice the measure of the second angle. So
x = second angle measure
2x = first angle measure
2x-20 = third angle measure
The sum of the angles of a triangle is 180 degrees:
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