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Question 945106: I need help with solving this problem (-6,7) perpendicular to -3x+4y=-23.I have to write it in slope-intercept form.
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! I need help with solving this problem (-6,7) perpendicular to -3x+4y=-23.I have to write it in slope-intercept form.
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first, we need to find the slope of:
-3x+4y=-23
do this by putting it into the "slope-intercept" form:
-3x+4y=-23
4y=3x-23
y=(3/4)x - 23/4
slope is 3/4
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new slope, for the new line to be perpendicular, must have a slope that is the "negative reciprocal" of the above or:
(3/4)m = -1
m = -4/3 (new slope)
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Now we have slope -4/3 and one point (-6,7)
plug above into "point-slope" form:
y - y1 = m(x-x1)
y - 7 = (-4/3)(x- -6)
y - 7 = (-4/3)(x+6)
y - 7 = (-4/3)x +(-4/3)6
y - 7 = (-4/3)x +(-4)2
y - 7 = (-4/3)x - 8
y = (-4/3)x - 8+7
y = (-4/3)x - 1 (answer in "slope-intercept" form)
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