SOLUTION: You and your friend live 12 miles apart. You leave home at the same time and travel toward each other. You walk at a rate of 4 miles per hour and your friend bicycles at a rate o

Algebra ->  Equations -> SOLUTION: You and your friend live 12 miles apart. You leave home at the same time and travel toward each other. You walk at a rate of 4 miles per hour and your friend bicycles at a rate o      Log On


   

Question 94502This question is from textbook McDougal Littell Algebra 1
: You and your friend live 12 miles apart. You leave home at the same time and travel toward each other. You walk at a rate of 4 miles per hour and your friend bicycles at a rate of 11 miles per hour. How long after you leave home will you meet? How far from home will each of you be? This question is from textbook McDougal Littell Algebra 1

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
4T+11T=12
15T=12
T=12/15
T=4/5 OR .8 HOURS TO MEET.
THE WALKER WILL BE:
4*.8=3.2 MILES FROM HOME
THE BIKER WILL BE:
11*.8=8.8 MILES FROM HOME.
PROOF
3.2+8.8=12
12=12