SOLUTION: The length of a rectangular backyard is 6 more than the width of the backyard. The perimeter of the backyard is 56 feet. What is the area of the backyard? (How would I work this ou

Algebra ->  Rectangles -> SOLUTION: The length of a rectangular backyard is 6 more than the width of the backyard. The perimeter of the backyard is 56 feet. What is the area of the backyard? (How would I work this ou      Log On


   



Question 945012: The length of a rectangular backyard is 6 more than the width of the backyard. The perimeter of the backyard is 56 feet. What is the area of the backyard? (How would I work this out?)
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
Width=W:Length=L=W+6 Perimeter=P=56 feet
P=2(L+W)
56 feet=2(L+W) Substitute for L
56 feet=2(W+6+W)
56 feet=2(2W+6)
56 feet=4W+12 Subtract 12 from each side
44 feet=4W Divide each side by 4
11 feet=W ANSWER 1: Width is 11 feet.
L=W+6=11+6=17 feet ANSWER 2: Length is 17 feet.
Area=L*W=(17 feet)(11 feet)=187 sq ft
ANSWER The area of the back yard is 187 sq ft
CHECK
P=2(L+W)
56 feet=2(17 feet+11 feet)
56 feet=2(28 feet)
56 feet=56 feet