SOLUTION: If you had a 10L bottle of solution that contained 40% acid, and needed to get it to a 35% acidic solution, how much liquid from a 20% bottle of solution would you need to add

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: If you had a 10L bottle of solution that contained 40% acid, and needed to get it to a 35% acidic solution, how much liquid from a 20% bottle of solution would you need to add      Log On

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Question 944815: If you had a 10L bottle of solution that contained 40% acid, and needed to get it to a 35% acidic solution, how much liquid from a 20% bottle of solution would you need to add
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+.4%2A10+=+4+ liters of acid in 10L bottle
Let +x+ = liters of 20% solution needed
+.2x+ = liters of acid in 20% solution
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+%28+4+%2B+.2x+%29+%2F+%28+10+%2B+x+%29+=+.35+
+4+%2B+.2x+=+.35%2A%28+10+%2B+x+%29+
+4+%2B+.2x+=+3.5+%2B+.35x+
+.15x+=+.5+
+x+=+3.333+
3 and 1/3 liters of the 20% solution are needed
check:
+%28+4+%2B+.2x+%29+%2F+%28+10+%2B+x+%29+=+.35+
+%28+4+%2B+.2%2A3.333+%29+%2F+%28+10+%2B+3.333+%29+=+.35+
+4.667+%2F+13.333+=+.35+
+4.667+=+4.667+
OK