SOLUTION: Chemicals A,B, and C cost .60, .40, and .80 per gram, respectively. They are mixed so that the number of grams of B is twice the number of grams of A and B is twice the number of

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Chemicals A,B, and C cost .60, .40, and .80 per gram, respectively. They are mixed so that the number of grams of B is twice the number of grams of A and B is twice the number of      Log On


   

Question 944809: Chemicals A,B, and C cost .60, .40, and .80 per gram, respectively. They are mixed so that the number of grams of B is twice the number of grams of A and B is twice the number of grams of A and is 3 less than the number of grams of C. The mixture is worth $11.40. How many grams of each chemical should be used?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The ratios of A, B, and C need to be made clear through symbolism.

Using A, B, C, for their corresponding quantities,
system%28B=2A%2CB=-3%2BC%29

Try to account for the cost of the mixture.
0.6A%2B0.4B%2B0.8C=11.40


Recheck the system of the ratios among A, B, and C. The system can be rearranged to show the quantities as functions of B.
system%28A=B%2F2%2CC=B%2B3%29.
Substitute these for A and C in the cost equation and have an equation in just the one variable, B.

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You do that.
Can you finish?