SOLUTION: Please help me with this equation using Elimination Method 5x-2y= 6 x+3y= -2

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Question 944792: Please help me with this equation using Elimination Method
5x-2y= 6
x+3y= -2

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

5%2Ax-2%2Ay=6
1%2Ax%2B3%2Ay=-2

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 5 and 1 to some equal number, we could try to get them to the LCM.

Since the LCM of 5 and 1 is 5, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -5 like this:

1%2A%285%2Ax-2%2Ay%29=%286%29%2A1 Multiply the top equation (both sides) by 1
-5%2A%281%2Ax%2B3%2Ay%29=%28-2%29%2A-5 Multiply the bottom equation (both sides) by -5


So after multiplying we get this:
5%2Ax-2%2Ay=6
-5%2Ax-15%2Ay=10

Notice how 5 and -5 add to zero (ie 5%2B-5=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%285%2Ax-5%2Ax%29-2%2Ay-15%2Ay%29=6%2B10

%285-5%29%2Ax-2-15%29y=6%2B10

cross%285%2B-5%29%2Ax%2B%28-2-15%29%2Ay=6%2B10 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

-17%2Ay=16

y=16%2F-17 Divide both sides by -17 to solve for y



y=-16%2F17 Reduce


Now plug this answer into the top equation 5%2Ax-2%2Ay=6 to solve for x

5%2Ax-2%28-16%2F17%29=6 Plug in y=-16%2F17


5%2Ax%2B32%2F17=6 Multiply



5%2Ax%2B32%2F17=6 Reduce



5%2Ax=6-32%2F17 Subtract 32%2F17 from both sides

5%2Ax=102%2F17-32%2F17 Make 6 into a fraction with a denominator of 17

5%2Ax=70%2F17 Combine the terms on the right side

cross%28%281%2F5%29%285%29%29%2Ax=%2870%2F17%29%281%2F5%29 Multiply both sides by 1%2F5. This will cancel out 5 on the left side.


x=14%2F17 Multiply the terms on the right side


So our answer is

x=14%2F17, y=-16%2F17

which also looks like

(14%2F17, -16%2F17)

Notice if we graph the equations (if you need help with graphing, check out this solver)

5%2Ax-2%2Ay=6
1%2Ax%2B3%2Ay=-2

we get



graph of 5%2Ax-2%2Ay=6 (red) 1%2Ax%2B3%2Ay=-2 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (14%2F17,-16%2F17). This verifies our answer.