SOLUTION: (Y^2/3)-(10y^1/3)+9=0 I added parentheses to clarify that it is y root 2/3 and 10y root 1/3. I need to solve using quadratic systems

Algebra ->  Rational-functions -> SOLUTION: (Y^2/3)-(10y^1/3)+9=0 I added parentheses to clarify that it is y root 2/3 and 10y root 1/3. I need to solve using quadratic systems      Log On


   

Question 944731: (Y^2/3)-(10y^1/3)+9=0
I added parentheses to clarify that it is y root 2/3 and 10y root 1/3. I need to solve using quadratic systems
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use a substitution,
u=y%5E%281%2F3%29
u%5E2=y%5E%282%2F3%29
So,
u%5E2-10u%2B9=0
%28u-1%29%28u-9%29=0
.
.
u-1=0
u=1
y%5E%281%2F3%29=1
y=1
.
.
u-9=0
u=9
y%5E%281%2F3%29=9
y=9%5E3
y=729