SOLUTION: Find two consecutive odd integers such that when the smaller is doubled, the results is 7 more than the larger integer.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find two consecutive odd integers such that when the smaller is doubled, the results is 7 more than the larger integer.      Log On


   

Question 944490: Find two consecutive odd integers such that when the smaller is doubled, the results is 7 more than the larger integer.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
S=smaller integer; L=larger integer=S+2
2S=L+7 Substitute for L
2S=(S+2)+7
2S=S+9 Subtract S from each side
S=9 ANSWER 1 Smaller Number is 9
L=S+2=9+2=11 ANSWER 2 Larger number is 11
CHECK:
Double the smaller is 7 more than the larger.
2S=L+7
2(9)=(11)+7
18=18