Question 944454: A triangle has a perimeter of 60 cm. 2 sides are equal, the third side is 10 cm more than the equal sides. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! Given triangle with sides A,B and C:
A+B+C=60 cm B=A; C=A+10=B+10 Substitute and solve for A
A+A+A+10=60 cm Subtract 10 from each side
3A=50 cm Divide each side by 3
ANSWER since A and B are equal sides
A=50/3
B=50/3
and: 50/3+50/3+C=60 cm
100/3+C=60 cm Subtract 100/3 from each side
C=180/3 cm-100/3 cm=80/3 cm ANSWER 3 Side C is 80/3 cm.
CHECK
A+B+C=60 cm
50/3 cm + 50/3 cm + 80/3 cm=60 cm
180/3cm=60cm
60cm=60cm
C=A+10cm
80/3cm=50/3cm+30cm
80/3 cm=80/3 cm
ANSWER Legs A and B=50/3 cm=16 2/3 cm and leg C=80/3 cm=26 2/3 cm