SOLUTION: Two cars leave towns 600 kilometers apart at the same time and travel toward each other. One cars rate is 14 kilometers per hour more than the other's. If they meet in 3 hours, wha
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Question 944267: Two cars leave towns 600 kilometers apart at the same time and travel toward each other. One cars rate is 14 kilometers per hour more than the other's. If they meet in 3 hours, what is the rate of the fastest car? Found 2 solutions by TimothyLamb, josmiceli:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = speed of slow car (kph)
y = speed of fast car (kph)
y = x + 14
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s = d/t
t = d/s
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speed of cars relative to each other:
s = x + y
s = x + x + 14
s = 2x + 14
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s = 600/3
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equate s's:
2x + 14 = 600/3
2x = 600/3 - 14
x = (600/3 - 14)/2
(600/3 - 14)/2
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copy and paste the above expression in to this calculator:
http://sooeet.com/math/scientific-calculator.php
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x = 93
y = x + 14
y = 93 + 14
y = 107
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answer:
y = speed of fast car (kph) = 107
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You can put this solution on YOUR website! Think of this as one cr standing still and the
other moving at the sum of their speeds
Let = the speed of the slower car in km/hr = the speed of the faster car in km/hr
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The faster car's speed is 107 km/hr
check:
OK
