Question 944056: A cat is chasing a mouse. a mouse is already 6ft ahead of the cat any running at a speed of 4ft per second. A cat is running at 6ft per second. What 2 equations can be created?
Answer by josgarithmetic(39621)   (Show Source):
You can put this solution on YOUR website! RT=D, and try to form a data table.
Account for positions of distances the cat and mouse will travel while cat is chasing. Assume they may go in only one direction, cat must travel further than the mouse, because mouse is ahead.
_______________rate__________time___________distance
CAT____________6_____________(___)___________d+6
MOUSE__________4_____________(___)____________d
The travel time will be the same for the Cat and for the Mouse. The situation starts at the same point on a time line but the distances and positions are different. The idea is that the cat will catch the mouse and will go d+6 feet while the mouse goes just d feet.
_______________rate__________time___________distance
CAT____________6______________t______________d+6
MOUSE__________4_____________ t______________d
USE the fundamental uniform rates fact for travel.
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