SOLUTION: the student concil is selling pens and pencils for a fundraiser. on monday they sold 29 pens and 13 penicals for 14.85 dollars . on tuesday they sold 22 pens and 13 pencils for a t

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: the student concil is selling pens and pencils for a fundraiser. on monday they sold 29 pens and 13 penicals for 14.85 dollars . on tuesday they sold 22 pens and 13 pencils for a t      Log On

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Question 943959: the student concil is selling pens and pencils for a fundraiser. on monday they sold 29 pens and 13 penicals for 14.85 dollars . on tuesday they sold 22 pens and 13 pencils for a total of 12.05 dollars . can you please help me thanks !!
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You didn't say what the problem was
looking for, but I'm sure you want :
Let +a+ = the cost of one pen
Let +b+ = the cost of one pencil
Find +a+ and +b+
-------------------------------
(1) +29a+%2B+13b+=+1485+ ( in cents )
(2) +22a+%2B+13b+=+1205+ ( in cents )
-----------------------------------
Subtract (2) from (1)
(1) +29a+%2B+13b+=+1485+
(2) +-22a+-+13b+=+-1205+
---------------------------
+7a+=+280+
+a+=+40+
and
(2) +22%2A40+%2B+13b+=+1205+
(2) +880+%2B+13b+=+1205+
(2) +13b+=+325+
(2) +b+=+25+
The cost of one pen is $.40
The cost of one pencil is $.25
--------------------------
check:
(1) +29a+%2B+13b+=+1485+
(1) +29%2A40+%2B+13%2A25+=+1485+
(1) +1160+%2B+325+=+1485+
(1) +1485+=+1485+
OK