SOLUTION: X^2 +4y^2 - 2x - 32y - 35 = 0 in standard form equation ellipse

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Question 943809: X^2 +4y^2 - 2x - 32y - 35 = 0 in standard form equation ellipse
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E2+%2B4y%5E2+-2x+-32y+-+35+=+0 in standard form equation ellipse

%28x%5E2+-2x+%29%2B4%28y%5E2-8y%29++=35 ...complete squares

%28x%5E2+-2x%2B1+%29-1%2B4%28y%5E2-8y%2B16%29+-4%2A16+=35

%28x+-1+%29%5E2-1%2B4%28y-4%29+%5E2-64+=35

%28x+-1+%29%5E2%2B4%28y-4%29+%5E2+=35%2B64%2B1

%28x+-1+%29%5E2%2B4%28y-4%29+%5E2+=100

%28x+-1+%29%5E2%2F100%2B4%28y-4%29+%5E2%2F100+=100%2F100

%28x+-1+%29%5E2%2F100%2B%28y-4%29+%5E2%2F25+=1