SOLUTION: Consider the expression y = rlog(n) (x+p)^w. An equivalent exponential expression is:
a. n^y = r(x+p)^w
b. n^y = (x+p)^w^r
c. n^y = (x+p)^w-r
d. n^y = (x+p)^w+r
Confused o
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Consider the expression y = rlog(n) (x+p)^w. An equivalent exponential expression is:
a. n^y = r(x+p)^w
b. n^y = (x+p)^w^r
c. n^y = (x+p)^w-r
d. n^y = (x+p)^w+r
Confused o
Log On
Question 943743: Consider the expression y = rlog(n) (x+p)^w. An equivalent exponential expression is:
a. n^y = r(x+p)^w
b. n^y = (x+p)^w^r
c. n^y = (x+p)^w-r
d. n^y = (x+p)^w+r
Confused on how to solve this question, I have many more just like this one and do not know the steps to take to solve this. What do I do?
Thank you Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Consider the expression y = rlog(n) (x+p)^w. An equivalent exponential
expression is:
-------
1st:: Apply the Rule:: alog(n)(x) = log(n)x^a to get:
y = log(n)[(x+p)^w]^r
------------------------------
base:: n
log = exponent = y
result = (x+p)^w^r
----------------------
Write in exponential form::
n^y = (x+p)^w^r
===============
Cheers,
Stan H.
-----------------
a. n^y = r(x+p)^w
b. n^y = (x+p)^w^r
c. n^y = (x+p)^w-r
d. n^y = (x+p)^w+r
(