SOLUTION: How can the polynomial 6d^4+9d^3-12d^2 be factored?

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Question 943631: How can the polynomial 6d^4+9d^3-12d^2 be factored?
Found 3 solutions by MathLover1, Theo, MathTherapy:
Answer by MathLover1(20850)   (Show Source):
You can put this solution on YOUR website!

Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website!
this is a quadratic formula in disguise.
the equation given is:
6d^4+9d^3-12d^2
set it equal to 0 to get:
6d^4+9d^3-12d^2 = 0
factor out d^2 and the equation becomes:
d^2 * (6d^2 + 9d - 12) = 0
this is a quadratic equation that can be factored using the quadratic formula.
the solutions are:
x = 0
x = .851
x = -2.351
the graph of the equation is shown below:

Answer by MathTherapy(10552)   (Show Source):
You can put this solution on YOUR website!
How can the polynomial 6d^4+9d^3-12d^2 be factored?

------ Factoring out GCF,
That's it, since is PRIME.