Question 943620: john has 31 coins consisting of quarters,dimes, and nickles. if he had one more dime, he would have just as many dimes as he has nickles and quarters put together. if the total value of johns coins is $4.70, how many coins of each kind does he have?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! john has 31 coins consisting of quarters,dimes, and nickles. if he had one more dime, he would have just as many dimes as he has nickles and quarters put together. if the total value of johns coins is $4.70, how many coins of each kind does he have?
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let d=number of dimes
let n=number of nickels
let q=number of quarters
..
d+n+q=31
n+q=31-d
..
d+1=n+q (One more dime=nickles and quarters put together)
d+1=31-d2d=30
d=15
..
n+q=d+1
n+q=15+1=16
q=16-n
..
.10d+.05n+.25q=4.70
.10d+.05n+.25(16-n)=4.70
.10*15+.05n+4-.25n=4.70
1.5-.20n+4=4.70
.20n=.80
n=4
q=16-n=12
how many coins of each kind does he have?
number of dimes=15
number of nickels=4
number of quarters=12
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