SOLUTION: f(x) = 2x^3+3x^2-12x+4 Good Morning, Please could you explain to me how to classify the stationary point(s) of the above function. I would then like to sketh its graph. I

Algebra ->  Test -> SOLUTION: f(x) = 2x^3+3x^2-12x+4 Good Morning, Please could you explain to me how to classify the stationary point(s) of the above function. I would then like to sketh its graph. I       Log On


   

Question 943501: f(x) = 2x^3+3x^2-12x+4
Good Morning,
Please could you explain to me how to classify the stationary point(s) of the above function. I would then like to sketh its graph.
I would appreciate if you could explain it in full providing calculations.
Kind regards
David
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = 2x^3+3x^2-12x+4
the graph of the equation looks like this,
+graph%28+300%2C+200%2C+-5%2C+5%2C+-50%2C+50%2C+2x%5E3%2B3x%5E2-12x%2B4+%29+
there are 3 zero points on this graph
x = -3.4233
x = 0.37808
x = 1.5453