SOLUTION: chuck and dana agree to meet in chicago for the weekend. Chuck travels 276 miles in the same time that dana travels 246 miles. If chuck's rate of travel is 5 mph more than dana's

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: chuck and dana agree to meet in chicago for the weekend. Chuck travels 276 miles in the same time that dana travels 246 miles. If chuck's rate of travel is 5 mph more than dana's      Log On

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Question 943221: chuck and dana agree to meet in chicago for the weekend. Chuck travels 276 miles in the same time that dana travels 246 miles. If chuck's rate of travel is 5 mph more than dana's, and they travel the same length, at what speed does chuck travel?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Chuck's rate is 276%2Ft+
Dana's rate is +246%2Ft+
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+276%2Ft+=246%2Ft+%2B+5+
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I can set up a ratio:

+276%2F246+=+%28%28+246%2Ft+%2B+5+%29%29+%2F+%28%28+246%2Ft+%29%29+
+%28+246%2Ft+%29%2A%28+46%2F41+%29+=+246%2Ft+%2B+5+
Multiply both sides by +t+
+5t+=+246%2A%28+46%2F41+%29+-+246+
+5t+=+246%2A%28+46%2F41+-+41%2F41+%29+
+5t+=+246%2A%28+5%2F41+%29+
+t+=+246%2F41+
+t+=+6+
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Chuck's rate is:
+276%2Ft+=+276%2F6+
+276%2F6+=+46+
46 mi/hr
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Dana's rate is:
+246%2Ft+=+246%2F6+
+246%2F6+=+41+
41 mi/hr
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check:
+%28+276%2Ft+%29+%2F+%28+246%2Ft+%29+=+%28+246%2Ft+%2B+5+%29+%2F+%28+246%2Ft+%29+
+46+%2F+41+=+%28+41+%2B+5+%29+%2F+41+
+46+=+41+%2B+5+
+46+=+46+
OK