Question 9432: Hello.
Please help me on my homework. I couldn't find a resonable answer to this problem. The problem is: The sum of Paul and Beth Taulman's ages now is 67 years. Eight years ago Paul was twice as old as Beth. How old is each now?
Please reply as soon as possible. Thank you for your time.
Julia
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Let P= Paul's age now
B = Beth's age now
P-8 = Paul's age 8 years ago
B-8 = Beth's age 8 years ago
First equation,
P+ B= 67, which means that B = 67 - P
Second equation,
P-8 = 2(B-8)
Substitute the B = 67 - P into the second equation:
P - 8 = 2(B - 8)
P - 8 = 2(67 - P - 8)
P - 8 = 134 - 2P - 16
P - 8 = 118 - 2P
Add + 2P to each side:
P + 2P - 8 = 118 - 2P + 2P
3P - 8 = 118
3P = 126
P = 42
B= 67 - P
B = 67 - 42
B = 25
Check: Eight years ago, Paul was 34 and Beth was 17, and Paul was twice as old as Beth.
R^2 at SCC
|
|
|
