SOLUTION: how many liters of a 10% alcohol solution must be mixed with 20 L of a 50% solution to get a 40% solution?

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: how many liters of a 10% alcohol solution must be mixed with 20 L of a 50% solution to get a 40% solution?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 943157: how many liters of a 10% alcohol solution must be mixed with 20 L of a 50% solution to get a 40% solution?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
how many liters of a 10% alcohol solution must be mixed with 20 L of a 50% solution to get a 40% solution?
==================
Add x liters.
10*x + 20*50 = (20 + x)*40