SOLUTION: Two records and three tapes cost $31. Three records and two tapes cost $29. Find the cost of each record and each tape.

Algebra ->  Human-and-algebraic-language -> SOLUTION: Two records and three tapes cost $31. Three records and two tapes cost $29. Find the cost of each record and each tape.       Log On


   



Question 943094: Two records and three tapes cost $31. Three records and two tapes cost $29. Find the cost of each record and each tape.

Answer by booklover15(10) About Me  (Show Source):
You can put this solution on YOUR website!
Records : r
Tape : t
2r+3t = $31
3r+2t = $29
Then we do elimination by making one of the variables the same value (in this case the r)
6r+9t = $93 (Make the r the same value by multiplying with 3)
6r+4t = $58. (Make the r the same value as the 6r by multiplying with 2)
__________- (we subtract the r to get the value of t)
5t = $35
t= $7
Then we substitute the r (choose either one of the equations to find the r)
2r+3t = $31
2r+3 x $7 = $31
2r = $31 - $21
2r = $10
r = $5