SOLUTION: Two records and three tapes cost $31. Three records and two tapes cost$21. Find the cost of each record and each tape.
Algebra ->
Finance
-> SOLUTION: Two records and three tapes cost $31. Three records and two tapes cost$21. Find the cost of each record and each tape.
Log On
You can put this solution on YOUR website! Let the cost of each record be x and the cost of each tape be y.
We get two simultaneous equations in x and y.
2x+3y=31 is the first equation.
3x+2y=21 is the second equation.
Multiplying the first equation with 3 we get
6x+9y=93.........equation 3.
Multiplying the second equation with 2 we get
6x+4y=42.........equation 4.
Subtracting 4 from 3 we get
9y-4y=93-42
5y=51
y=10.2
Substituting in equation 1 we get,
2x+30.6=31
x=0.2
The cost of a record is $0.2(20 cents) and the cost of a tape is $10.2(10 dollars and 20 cents).