SOLUTION: Solve this quadratic equation. (6)/(2x-1)=(4)/(x+1) This is what I got, after multiplying the equation by the LCM (2x-1). 6=(4)/(x+1) I think the non-permissible values ar

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Solve this quadratic equation. (6)/(2x-1)=(4)/(x+1) This is what I got, after multiplying the equation by the LCM (2x-1). 6=(4)/(x+1) I think the non-permissible values ar      Log On


   

Question 943034: Solve this quadratic equation.
(6)/(2x-1)=(4)/(x+1)
This is what I got, after multiplying the equation by the LCM (2x-1).
6=(4)/(x+1)
I think the non-permissible values are 0 & -1.
Please help me fix/complete the equation. Thanks!
Found 2 solutions by reviewermath, MathTherapy:
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
6%2F%282x-1%29+=+4%2F%28x%2B1%29
The LCD is equal to (2x-1)(x+1).
Multiply both sides by the LCD, the result is
6(x + 1) = 4(2x - 1)
6x + 6 = 8x - 4
-2x = -10
Therefore x+=+highlight%285%29

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

Solve this quadratic equation.
(6)/(2x-1)=(4)/(x+1)
This is what I got, after multiplying the equation by the LCM (2x-1).
6=(4)/(x+1)
I think the non-permissible values are 0 & -1.
Please help me fix/complete the equation. Thanks! 
6%2F%282x+-+1%29+=+4%2F%28x+%2B+1%29, with x+%3C%3E+system%28%281%2F2%29_or%2C-+1%29

4(2x - 1) = 6(x + 1) ------- Cross-multiplying

8x - 4 = 6x + 6

8x - 6x = 6 + 4

2x = 10

x+=+10%2F2, or highlight_green%285%29      

You can do the check!! 

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