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Question 942891: 3(x+3)^2+19=0
Solve by extracting the roots
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! 3(x+3)^2 + 19 = 0
3(x+3)(x+3) + 19 = 0
3(xx + 6x + 9) + 19 = 0
3xx + 18x + 27 + 19 = 0
3xx + 18x + 46 = 0
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the above quadratic equation is in standard form, with a=3, b=18 and c=46
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
3 18 46
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the quadratic has two complex roots at:
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x = -3 + (2.51661148)i
x = -3 - (2.51661148)i
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now, use a different method:
solve by taking the square root:
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3(x+3)^2 + 19 = 0
3(x+3)^2 = -19
(x+3)^2 = -19/3
sqrt( (x+3)^2 ) = +/- sqrt( -19/3 )
x+3 = +/- sqrt( -19/3 )
x = -3 +/- sqrt( -19/3 )
x = -3 +/- sqrt( 19/3 )sqrt( -1 )
x = -3 +/- sqrt( 19/3 )i
x = -3 +/- (2.51661148)i
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x = -3 + (2.51661148)i
x = -3 - (2.51661148)i
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