SOLUTION: find three consecutive integers such that the sum of the first and three times the second is eighteen less than five times the third integer.

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Question 942798: find three consecutive integers such that the sum of the first and three times the second is eighteen less than five times the third integer.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
Three consecutive integers:I, I+1, I+2
Sum of first and three times second: I+(3(I+1))
is 18 less than 5 times the third 5(I+2)-18
I+3I+3=5I+10-18
4I+3=5I-8 add 8 to each side
4I+3+8=5I-8+8
4I+11=5I subtract 4I from each side
4I+11-4I=5I-4I
11=I The first integer is 11
I+1=12 The second integer is 12
I+2=13 The third integer is 13
CHECK
11+3(12)=5(13)-18
11+36=65-18
47=47