SOLUTION: a man has a daughter and son . The son is 3 years older than the daughter. In one year the man will be 6 times as old as the daughter is now. In ten years, the man will be fourteen

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Question 942769: a man has a daughter and son . The son is 3 years older than the daughter. In one year the man will be 6 times as old as the daughter is now. In ten years, the man will be fourteen years older than the combined ages of his children at that time . what is the man present age ?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
m, s, d, their ages now.


The transcribed description:
system%28s=d%2B3%2Cm%2B1=6d%2Cm%2B10=14%2B%28d%2B10%29%2B%28s%2B10%29%29

Three linear equations in the three unknown variables. Simplify and solve the system.