SOLUTION: A man has a daughter and son . The son is 3 years older than the daughter . In one year the man will be 6 times as old as the daughter is now. In 10 years,the man will be fourtee

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Question 942763: A man has a daughter and son .
The son is 3 years older than the daughter . In one year the man will be 6 times as old as the daughter is now. In 10 years,the man will be fourteen years older than the combined ages of his children at that time . What is the man present age?
Answer by Merciful(5) About Me  (Show Source):
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Let x be the daughter's present age
The Son's present age is (x + 3)
In one year the man will be 6x
In 10 years the man will be (x + 10) (x + 13) + 14
From this we can say the man's present age is 6x-1
And also in 10 years the man will be 6x + 9
So:::(x + 10) (x + 13) + 14=6x + 9
4x=28
x=7
The man's present age = 6x-1
=6(7)-1
=41