SOLUTION: Hello! Here is the question I need help understanding: "Write an equation for a linear function whose graph has the given characteristics: (-2,2)(2,-12) I have tried m=y2-y1 ov

Algebra ->  Functions -> SOLUTION: Hello! Here is the question I need help understanding: "Write an equation for a linear function whose graph has the given characteristics: (-2,2)(2,-12) I have tried m=y2-y1 ov      Log On


   

Question 942732: Hello! Here is the question I need help understanding:
"Write an equation for a linear function whose graph has the given characteristics: (-2,2)(2,-12)
I have tried m=y2-y1 over x2-x1, and I get -14/4 but that answer comes back incorrect. Please tell me what I'm doing wrong. Thank you so much
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
You have the right idea.

Subscript 1, (-2,2);
Subscript 2, (2,-12);
m=%28-12-2%29%2F%282-%28-2%29%29=-14%2F4=-7%2F2.

Now, take your pick: Use either slope-intercept form or use point-slope form.

If slope-intercept,
y=mx+b, and you know m.
b=y-mx, and just pick either of the given points for x and y.