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Question 942700: find the roots for: (2s-5)(3s+7)
then, expand the factors into a quadratic equation
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! (2s-5)(3s+7)
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root 1:
2s-5 = 0
2s = 5
s = 5/2
s = 2.5
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root 2:
3s+7 = 0
3s = -7
s = -7/3
s = -2.33333333
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expand the quadratic:
y = (2s-5)(3s+7)
y = 6ss - s - 35
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check by finding the roots again, but using a different method:
6ss - s - 35 = 0
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the above quadratic equation is in standard form, with a=6, b=-1 and c=-35
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
6 -1 -35
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the quadratic has two real roots at:
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s = 2.5
s = -2.33333333
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