SOLUTION: Can you please help me with this problem thank you. The length of a rectangle is four feet more than twice its width. If the area of the rectangle is 160 square feet, its length

Algebra ->  Radicals -> SOLUTION: Can you please help me with this problem thank you. The length of a rectangle is four feet more than twice its width. If the area of the rectangle is 160 square feet, its length      Log On


   

Question 942344: Can you please help me with this problem thank you.
The length of a rectangle is four feet more than twice its width. If the area of the rectangle is 160 square feet, its length is __________ feet.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for area is:
+A+=+L%2AW+
+L+=+2W+%2B+4+ ft
+A+=+160+ ft2
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by substitution:
+160+=+%28+2W+%2B+4+%29%2AW+
+160+=+2W%5E2+%2B+4W+
+W%5E2+%2B+2W+-+80+
+%28+W+%2B+10+%29%2A%28+W+-+8+%29+
+W+=+8+ ( can only use the positive solution )
and
+L+=+2W+%2B+4+
+L+=+2%2A8+%2B+4+
+L+=+20+
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The length is 20 ft