SOLUTION: A local hamburger shop sold a combined total of 491 hamburgers and cheeseburgers on Saturday. There were 59 fewer cheeseburgers sold than hamburgers. How many hamburgers we

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: A local hamburger shop sold a combined total of 491 hamburgers and cheeseburgers on Saturday. There were 59 fewer cheeseburgers sold than hamburgers. How many hamburgers we      Log On

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Question 942243: A local hamburger shop sold a combined total of
491
hamburgers and cheeseburgers on Saturday. There were
59
fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Saturday?

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
H=no of hamburgers C=no of cheeseburgers
C=H-59
H+C=491 substitute above for C and solve for H
H+(H-59)=491
2H-59=491 Add 59 to each side
2H-59+59=491+59
2H=550 Divide both sides by 2
2H/2=550/2
H=275 Number of hamburgers = 275
C=275-59=216 Number of cheeseburgers=216
CHECK:
H+C=491
275+216=491
491=491