SOLUTION: What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 40% solution

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Question 942184: What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 40% solution
Answer by stanbon(75887) About Me  (Show Source):
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What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 40% solution
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Equation::
acid + acid = acid
0.50x + 0.20(600-x) = 0.40*600
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50x + 20*600 - 20x = 40*600
30x = 20*600
x = 20*20
x = 400 mL (amt. of 50% solution needed)
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Cheers,
Stan H.
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