SOLUTION: For the problem given below, set up an equation and solve. Show all work (including what your variables represent), detailing each step, to ensure that I am able to follow your wo
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Question 941776: For the problem given below, set up an equation and solve. Show all work (including what your variables represent), detailing each step, to ensure that I am able to follow your work. Clearly state your solution. Please and thank you
The problem:
If the product of two consecutive positive even integers is equal to 168, then what are the integers. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! Two consecutive even integers, I and I+2
Product is 168, (I)(I+2)=168 Subtract 168 from each side
Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=676 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: 12, -14.
Here's your graph:
The results are 12 and -14. The integer specified is positive, so I=12 and the second is I+2=14
CHECK:the product of 12 and 14 is (12)(14}=168
The ANSWER (SOLUTION) Is 12 and 14