SOLUTION: http://i.imgur.com/60aUUFr.png Match each equation with the graph of f, g, m, or n in the figure. (A) y = (0.2)^x (B) y = 2^x (C) y = (1/3)^x (D) y = 4^x

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: http://i.imgur.com/60aUUFr.png Match each equation with the graph of f, g, m, or n in the figure. (A) y = (0.2)^x (B) y = 2^x (C) y = (1/3)^x (D) y = 4^x      Log On


   

Question 941676: http://i.imgur.com/60aUUFr.png
Match each equation with the graph of f, g, m, or n in the figure.
(A) y = (0.2)^x (B) y = 2^x
(C) y = (1/3)^x (D) y = 4^x
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
(A) y+=+%280.2%29%5Ex
(B) y+=+2%5Ex
(C) y+=+%281%2F3%29%5Ex+
(D) y+=+4%5Ex
if x=0 all given functions will be 1; so, all of them have same y-intercept and it is 1
since
(A) y+=+%280.2%29%5Ex =>y+=+%282%2F10%29%5Ex =>y+=+%281%2F5%29%5Ex=>y+=+5%5E%28-x%29, have graph at II quadrant
and (C) y+=+%281%2F3%29%5Ex+ =>y+=+%281%2F3%29%5Ex=>y+=+3%5E%28-x%29, they have graph at II quadrant
so, A and C could be only f and g
since f is closer to y-axis then g, means it growth is "bigger" and "faster" then g; so, we can say
highlight%28f%29 is highlight%28y=%281%2F3%29%5Ex%29 then
highlight%28g%29 is highlight%28y+=+%280.2%29%5Ex%29
in I quadrant we have B and D, evidently D is growing "bigger" and "faster" then B, so
highlight%28n%29 is highlight%28y=2%5Ex%29
highlight%28m%29+is highlight%28y=4%5Ex%29