SOLUTION: If it takes 3men 56hours to dig a hole 4mX6mX5m, and two of the men work twice
as fast as the third,find the number of hours that will take the two faster men to dig this hole t
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as fast as the third,find the number of hours that will take the two faster men to dig this hole t
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Question 941551: If it takes 3men 56hours to dig a hole 4mX6mX5m, and two of the men work twice
as fast as the third,find the number of hours that will take the two faster men to dig this hole together. ( answer is 70hours - show your solution ) Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! If it takes 3men 56hours to dig a hole 4mX6mX5m, and two of the men work twice
as fast as the third,find the number of hours that will take the two faster men to dig this hole together.
let x=amt of work slower man can do in one hr
his work rate=1/x
2/x=work rate of each faster man
280/x=1
x=280
..
2x/280+2x/280=1
4x/280=1
4x=280
x=70 hrs
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