SOLUTION: My kids asked for help on this one. I worked at it and always came up with 60 as the answer, but it should be 15. It is on page 41, problem 6:
The measure of the supplement of a
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-> SOLUTION: My kids asked for help on this one. I worked at it and always came up with 60 as the answer, but it should be 15. It is on page 41, problem 6:
The measure of the supplement of a
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Question 94119This question is from textbook Geometry
: My kids asked for help on this one. I worked at it and always came up with 60 as the answer, but it should be 15. It is on page 41, problem 6:
The measure of the supplement of an angle is 60 less than three times the measure of the complement of the angle. Find the measure of the angle. This question is from textbook Geometry
You can put this solution on YOUR website! x=the unknown angle
complement=90-x
supplement=180-x
The supplement needs 60 to be equal to 3 times the compliment.
180-x+60=3(90-x)
240-x=270-3x
add 3x-240 to both sides. 2x=30
x=15
Ed Jones
You can put this solution on YOUR website! Let's call the angle A.
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The measure of the supplement of this angle is 180 - A
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The measure of the complement of this angle is 90 - A
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The problem now tells you that the measure of the supplement of this angle (180 - A) is
60 less than 3 times the complement of the angle (90 - A). So we need to write 3 times the
complement and subtract 60 from it to get 3(90 - A) - 60.
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We can now set these two equal. That is:
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180 - A = 3(90 -A) - 60
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Do the distributed multiplication on the right side and the equation becomes:
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180 - A = 270 - 3A - 60
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On the right side, combine the 270 and the - 60 into 210 to make the equation:
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180 - A = -3A + 210
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Now subtract 180 from both sides to get rid of the 180 on the left side. The equation
then becomes:
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-A = -3A + 30
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Now add 3A to both sides and you get:
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2A = 30
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and divide both sides by 2 to find that A is 15 degrees.
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Hope this helps you to find where you went astray.
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